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C Program to Check Prime Number Using Efficient Logic

  Introduction A prime number is a number that has exactly two distinct positive divisors: 1 and itself. In this program, we check whether a given number is prime or not using a simple and efficient logic. This type of program is commonly used in mathematics, competitive programming, and basic algorithm learning for beginners in C programming. Problem Statement The task is to write a C program that determines whether a given integer is a prime number or not. The program takes a single integer input from the user and analyzes its divisibility. If the number has no divisors other than 1 and itself, it should be identified as a prime number; otherwise, it is not prime. This problem is important in number theory and has practical relevance in areas such as cryptography, data validation, and algorithm design.  Algorithm / Logic Explanation To check whether a number is prime, we need to verify that it is not divisible by any number other than 1 and itself. The algorithm follows a si...

C Program to Find the Third Smallest Element Without Sorting

๐Ÿ” C Program to Find the Third Smallest Element Without Sorting

#include <stdio.h>

int main()
{
    int num, a[100];
    printf("Enter the size of the array:\n");
    scanf("%d", &num);

    if (num < 3)
    {
        printf("Invalid! Need at least 3 elements to find the third smallest element.\n");
        return 1;
    }

    printf("Enter %d elements:\n", num);
    for (int i = 0; i < num; i++)
    {
        scanf("%d", &a[i]);
    }

    int first, second, third;

    // Initialize first, second, third with the smallest 3
    if (a[0] <= a[1] && a[0] <= a[2])
    {
        first = a[0];
        if (a[1] <= a[2])
        {
            second = a[1];
            third = a[2];
        }
        else
        {
            second = a[2];
            third = a[1];
        }
    }
    else if (a[1] <= a[0] && a[1] <= a[2])
    {
        first = a[1];
        if (a[0] <= a[2])
        {
            second = a[0];
            third = a[2];
        }
        else
        {
            second = a[2];
            third = a[0];
        }
    }
    else
    {
        first = a[2];
        if (a[0] <= a[1])
        {
            second = a[0];
            third = a[1];
        }
        else
        {
            second = a[1];
            third = a[0];
        }
    }

    for (int i = 3; i < num; i++)
    {
        if (a[i] < first)
        {
            third = second;
            second = first;
            first = a[i];
        }
        else if (a[i] < second && a[i] != first)
        {
            third = second;
            second = a[i];
        }
        else if (a[i] < third && a[i] != second && a[i] != first)
        {
            third = a[i];
        }
    }

    if (first == second || second == third)
    {
        printf("There is no distinct third smallest element.\n");
    }
    else
    {
        printf("The third smallest element is: %d\n", third);
    }

    return 0;
}
  

๐Ÿ“ Explanation:

This program identifies the third smallest distinct element without sorting the array. It initializes the smallest three manually and adjusts their values during iteration while avoiding duplicates.

๐Ÿ’ก Sample Output:

Enter the size of the array:
7
Enter 7 elements:
5 1 9 2 4 1 6
The third smallest element is: 4
  

๐Ÿ” Keywords:

C program to find third minimum value, no sorting, array interview questions in C, C coding logic, array manipulation

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