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C Program to Solve Two Sum Using Brute Force (With Algorithm & Output)

 Introduction The Two Sum problem is a popular coding interview question where we must find two indices of an array whose values add up to a given target. This program demonstrates a simple brute-force solution in C using nested loops and dynamic memory allocation. Problem Statement Given an integer array and a target value, return the indices of the two numbers such that they add up to the target. Each input has exactly one solution, and the same element cannot be used twice. The result should return the indices, not the values. If no solution exists, return NULL.  Algorithm / Logic Explanation Start the program. Traverse the array using a loop from index 0 to numsSize - 1 . Inside this loop, use another loop starting from i + 1 to numsSize - 1 . For every pair (i, j) , check if nums[i] + nums[j] == target . If condition becomes true: Allocate memory for 2 integers using malloc() . Store indices i and j . Set returnSize = 2 . Return the result poi...

WAP to find the greatest of given 3 numbers

Description :  

You should read 3 integers from user and find the maximum of three numbers.

Sample Execution : 

Test case 1 : 

Enter the three numbers : 10 20 30

Max of three number is 30 

Test case 2 :

Enter the three numbers : 90 20 40

Max of three number is 90 

PROGRAM:

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#include<stdio.h>

int main()

{

int num1,num2,num3;

    printf("Enter the three numbers:");

    scanf("%d %d %d",&num1,&num2,&num3);

    if(num1>=num2 && num1>num3)

    {

    printf("Max of three number is %d",num1);

    }

    else if (num2>=num1 && num2>=num3)

    {

        printf("Max of three number is %d",num2);

    }

    else if(num3>=num1 && num3>=num2) 

    printf("Max of three number is %d",num3);

}

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sample input;

Enter three numbers:10 20 30

sample output:

Max of three numberis 30

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