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C Program to Solve Two Sum Using Brute Force (With Algorithm & Output)

 Introduction The Two Sum problem is a popular coding interview question where we must find two indices of an array whose values add up to a given target. This program demonstrates a simple brute-force solution in C using nested loops and dynamic memory allocation. Problem Statement Given an integer array and a target value, return the indices of the two numbers such that they add up to the target. Each input has exactly one solution, and the same element cannot be used twice. The result should return the indices, not the values. If no solution exists, return NULL.  Algorithm / Logic Explanation Start the program. Traverse the array using a loop from index 0 to numsSize - 1 . Inside this loop, use another loop starting from i + 1 to numsSize - 1 . For every pair (i, j) , check if nums[i] + nums[j] == target . If condition becomes true: Allocate memory for 2 integers using malloc() . Store indices i and j . Set returnSize = 2 . Return the result poi...

Write a program to check whether character is Upper Case, Lower Case or Digit

 Description : 

You have to read a characer and check it is  upper case, lower case, digit or none.of.above.

Sample Execution : 

Test case 1 : 

Enter the character : A

The character is Upper Case.

Test case 2 :

Enter the character : 5

The character is Digit.

Test case 3 :

Enter the character : !

The character not an alphabet or digit.

PROGRAM:

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#include<stdio.h>

int main()

{

    char ch;

  printf("Enter a character or digit;");

    scanf("%c",&ch);

     if(ch>='A' && ch<='Z')

   { printf("%c The character is Upper Case",ch );}

    else if(ch>='a' && ch<='z')

  {

       printf("%c The character is Lower Case",ch);

   }

   else if (ch>='0' && ch<='9')

   {

       printf("The character is Digit.");

   }

   else

   {

       printf("The character  not an  alphabet or digit.");

   }

   }

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sampleoutput;Enter a character:A

sampleinput;The character is Upper case.



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