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Solve LeetCode 3 Longest Substring Without Repeating Characters in C++ using the sliding window

Longest Substring Without Repeating Characters in C++ LeetCode 3 · sliding window · last index array Table of Contents Problem Statement Approach Algorithm C++ Program Input Sample Output Output Explanation Dry Run Flow of Execution Time Complexity Space Complexity Applications Key Points Interview Questions Frequently Asked Questions Conclusion Problem Statement 3. Longest Substring Without Repeating Characters Given a string s , find the length of the longest substring that contains no repeating characters. A substring is a continuous part of the string, so "pwke" is a subsequence of "pwwkew" but not a substring. Approach We use a sliding window . The window is the part of the string between start and end , and we always keep it free of repeated characters. An array lastIndex of size 128 remembers the most recent position of every ASCII ...

write a program to implement atoi function in c

Description:

    • int my_atoi(const char *s)
      • The function will recieve a string and covert the number stored in the string into exact integer number.
      • Return the number.
Pr-requisites:-
    • Functions
    • Pointers

Objective: -

  • To understand the concept of
    • Functions and Pointers
Inputs: -
          String, String and Integer

Sample execution: -

Test Case 1 :
Enter a numeric string: 12345

String to integer is 12345

Test Case 2 :
Enter a numeric string: -12345

String to integer is -12345

Test Case 3 :
Enter a numeric string: +12345

String to integer is 12345

Test Case 4 :
Enter a numeric string: +-12345

String to integer is 0

Test Case 5 :
Enter a numeric string: 12345-

String to integer is 12345

Test Case 6 :
Enter a numeric string: abcd12345

String to integer is 0

Test Case 7 :
Enter a numeric string: 12345abcd

String to integer is 12345


PROGRAM

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#include <stdio.h>

int my_atoi(const char str[])

{

    int i=0,a=0,b=0,t=0;

    while(str[i]!='\0')

    {

        if(str[0]=='*')

        {

            break;

        }

        if((str[0]=='-' && str[1]=='+') || (str[0]=='+' && str[1]=='-') || (str[0]=='+' && str[1]=='+') || (str[0]=='-' && str[1]=='-'))

        {

            break;

        }

        if((str[i]>='a' && str[i]<='z') || (str[i]>='A' && str[i]<='Z'))

        {

            break;

        }

        if(str[0]=='-')

        {

            t=1;

         //   i++;

        }

        if(str[i]>='0' && str[i]<='9')

        {

            b=str[i]-48;

            a=a*10+b;

            

        }

        i++;

    }

    if(t==1)

    return -a;

    else

    return a;

}

int main()

{

    char str[20];

      printf("Enter a numeric string : ");

    scanf("%s", str);

    int res = my_atoi(str);

    printf("String to integer is %d\n", res);

}

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