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C++ Program to Perform Linear Search on a Vector

  C++ Program to Perform Linear Search on a Vector Introduction In this C++ program, we will learn how to perform a Linear Search on a vector. The program first takes the size of the vector and its elements as input. Then it asks the user for the element to search. If the element is found, it displays the index where it is located. Otherwise, it displays a message indicating that the element is not found. C++ Program #include<bits/stdc++.h> using namespace std; int main() { int num, search, found = 0; cout << "Enter the size of the vector:" << endl; cin >> num; vector<int> v(num); cout << "Enter " << num << " elements in vector:" << endl; for(int i = 0; i < num; i++) { cin >> v[i]; } cout << "Enter element that you want to search:" << endl; cin >> search; for(int i = 0; i < num; i++) { ...

write a program to implement atoi function in c

Description:

    • int my_atoi(const char *s)
      • The function will recieve a string and covert the number stored in the string into exact integer number.
      • Return the number.
Pr-requisites:-
    • Functions
    • Pointers

Objective: -

  • To understand the concept of
    • Functions and Pointers
Inputs: -
          String, String and Integer

Sample execution: -

Test Case 1 :
Enter a numeric string: 12345

String to integer is 12345

Test Case 2 :
Enter a numeric string: -12345

String to integer is -12345

Test Case 3 :
Enter a numeric string: +12345

String to integer is 12345

Test Case 4 :
Enter a numeric string: +-12345

String to integer is 0

Test Case 5 :
Enter a numeric string: 12345-

String to integer is 12345

Test Case 6 :
Enter a numeric string: abcd12345

String to integer is 0

Test Case 7 :
Enter a numeric string: 12345abcd

String to integer is 12345


PROGRAM

----------------------------------------------------------------------------------------------------------------------------


#include <stdio.h>

int my_atoi(const char str[])

{

    int i=0,a=0,b=0,t=0;

    while(str[i]!='\0')

    {

        if(str[0]=='*')

        {

            break;

        }

        if((str[0]=='-' && str[1]=='+') || (str[0]=='+' && str[1]=='-') || (str[0]=='+' && str[1]=='+') || (str[0]=='-' && str[1]=='-'))

        {

            break;

        }

        if((str[i]>='a' && str[i]<='z') || (str[i]>='A' && str[i]<='Z'))

        {

            break;

        }

        if(str[0]=='-')

        {

            t=1;

         //   i++;

        }

        if(str[i]>='0' && str[i]<='9')

        {

            b=str[i]-48;

            a=a*10+b;

            

        }

        i++;

    }

    if(t==1)

    return -a;

    else

    return a;

}

int main()

{

    char str[20];

      printf("Enter a numeric string : ");

    scanf("%s", str);

    int res = my_atoi(str);

    printf("String to integer is %d\n", res);

}

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