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Solve LeetCode 3 Longest Substring Without Repeating Characters in C++ using the sliding window

Longest Substring Without Repeating Characters in C++ LeetCode 3 · sliding window · last index array Table of Contents Problem Statement Approach Algorithm C++ Program Input Sample Output Output Explanation Dry Run Flow of Execution Time Complexity Space Complexity Applications Key Points Interview Questions Frequently Asked Questions Conclusion Problem Statement 3. Longest Substring Without Repeating Characters Given a string s , find the length of the longest substring that contains no repeating characters. A substring is a continuous part of the string, so "pwke" is a subsequence of "pwwkew" but not a substring. Approach We use a sliding window . The window is the part of the string between start and end , and we always keep it free of repeated characters. An array lastIndex of size 128 remembers the most recent position of every ASCII ...

Write a program to replace each string of one or more blanks by a single blank in c

Description:

  • Input string:
    • Pointers         are      sharp           knives.
  • Output String:
    • Pointers are sharp knives.
  • Blank can be spaces or tabs. (replace with single space).
Pr-requisites:-
  • Functions
  • Pointers

Objective: -

  • To understand the concept of
    • Functions, Arrays, and Pointers

Inputs: -

  • String with multi-spaces between words
Sample execution: -
Test Case 1:

Enter the string with more spaces in between two words
Pointers     are               sharp     knives.
Pointers are sharp knives.

Test Case 2:

Enter the string with more spaces in between two words

Welcome                to Emertxe

Welcome to Emertxe

Test Case 1:

Enter the string with more spaces in between two words
Welcome to india

Welcome to india

PROGRAM 


---------------------------------------------------------------------------------------------------------

#include <stdio.h>
#include<string.h>
void space(char str[])
{
    int i,k=0;
    while(str[k]!='\0')
    {
        if((str[k]==' ' && str[k+1]==' ') || (str[k]=='\t' && str[k+1]=='\t'))
        {
            i=k;
            while(str[i]!='\0')
            {
                str[i]=str[i+1];
                i++;
            }
             k--;
        }
        k++;
    }
}
int main()
{
    char str[200];
    
   // printf("Enter the string with more spaces in between two words\n");
    scanf("%[^\n]", str);
    
   space(str);
    
    printf("%s\n", str);
}
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