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C Program to Solve Two Sum Using Brute Force (With Algorithm & Output)

 Introduction The Two Sum problem is a popular coding interview question where we must find two indices of an array whose values add up to a given target. This program demonstrates a simple brute-force solution in C using nested loops and dynamic memory allocation. Problem Statement Given an integer array and a target value, return the indices of the two numbers such that they add up to the target. Each input has exactly one solution, and the same element cannot be used twice. The result should return the indices, not the values. If no solution exists, return NULL.  Algorithm / Logic Explanation Start the program. Traverse the array using a loop from index 0 to numsSize - 1 . Inside this loop, use another loop starting from i + 1 to numsSize - 1 . For every pair (i, j) , check if nums[i] + nums[j] == target . If condition becomes true: Allocate memory for 2 integers using malloc() . Store indices i and j . Set returnSize = 2 . Return the result poi...
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C Program to Print Descending Number Pattern Using Loops

Descending Number Pattern in C

Descending Number Pattern in C

This C program prints a number pattern where each row contains numbers in ascending order, but the total number of elements decreases with each row. This is done using nested for loops.

✅ C Program Code:


#include <stdio.h>

int main()
{
    int num;
    printf("Enter the number:\n");
    scanf("%d", &num);
    for (int i = num; i >= 1; i--)
    {
        for (int j = 1; j <= i; j++)
        {
            printf("%d ", j);
        }
        printf("\n");
    }
}

💡 Explanation:

  • User Input: The program asks for a number (e.g., 5).
  • Outer Loop: Runs from the input number down to 1.
  • Inner Loop: Prints numbers from 1 to the current value of i.

💻 Sample Output:

Enter the number:
5
1 2 3 4 5
1 2 3 4
1 2 3
1 2
1

🔍 Keywords:

C pattern program, descending number pattern in C, reverse triangle pattern C, number logic in C, beginner friendly C programs, nested loop patterns

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