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C++ Program to Perform Linear Search on a Vector

  C++ Program to Perform Linear Search on a Vector Introduction In this C++ program, we will learn how to perform a Linear Search on a vector. The program first takes the size of the vector and its elements as input. Then it asks the user for the element to search. If the element is found, it displays the index where it is located. Otherwise, it displays a message indicating that the element is not found. C++ Program #include<bits/stdc++.h> using namespace std; int main() { int num, search, found = 0; cout << "Enter the size of the vector:" << endl; cin >> num; vector<int> v(num); cout << "Enter " << num << " elements in vector:" << endl; for(int i = 0; i < num; i++) { cin >> v[i]; } cout << "Enter element that you want to search:" << endl; cin >> search; for(int i = 0; i < num; i++) { ...

C Program: Union and Nibble Sum of a Hexadecimal Number

C Program: Union and Nibble Sum

๐Ÿ”ท C Program: Union and Nibble Sum of a Hexadecimal Number

#include <stdio.h>

union byteunion
{
    unsigned int full_word;
    unsigned char bytes[4];
};

int main( )
{
    union byteunion data;
    scanf("%x", &data.full_word);

    int upper_sum = 0, lower_sum = 0;

    printf("\nBytes: ");
    for (int i = 3; i >= 0; i--)
    {
        printf("0x%02X", data.bytes[i]);
        if (i != 0)
            printf(", ");
    }

    for (int i = 0; i < 4; i++)
    {
        int byte = data.bytes[i];
        int upper = byte / 16;
        int lower = byte % 16;
        upper_sum += upper;
        lower_sum += lower;
    }

    printf("\nUpper nibble addition: 0x%02x", upper_sum);
    printf("\nLower nibble addition: 0x%02X\n", lower_sum);
}
  

๐Ÿ“˜ Explanation:

This program demonstrates how to use a union in C to access individual bytes of a 32-bit hexadecimal input.

๐Ÿ”น A union is used to share memory between an unsigned int and an array of 4 bytes.
๐Ÿ”น The user inputs a 32-bit hexadecimal number.
๐Ÿ”น The program prints all 4 bytes from most significant to least significant.
๐Ÿ”น Each byte is split into upper and lower 4-bit nibbles.
๐Ÿ”น It then calculates and displays the sum of upper and lower nibbles separately in hexadecimal format.

๐Ÿ” Sample Output:

Input:
12345678

Output:
Bytes: 0x12, 0x34, 0x56, 0x78
Upper nibble addition: 0x15
Lower nibble addition: 0x14
    

๐Ÿท️ Keywords:

C union example, hexadecimal byte access, nibble sum, bitwise manipulation, memory sharing in C, byte array, 32-bit hex analysis

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