Skip to main content

Featured

C++ Program to Perform Linear Search on a Vector

  C++ Program to Perform Linear Search on a Vector Introduction In this C++ program, we will learn how to perform a Linear Search on a vector. The program first takes the size of the vector and its elements as input. Then it asks the user for the element to search. If the element is found, it displays the index where it is located. Otherwise, it displays a message indicating that the element is not found. C++ Program #include<bits/stdc++.h> using namespace std; int main() { int num, search, found = 0; cout << "Enter the size of the vector:" << endl; cin >> num; vector<int> v(num); cout << "Enter " << num << " elements in vector:" << endl; for(int i = 0; i < num; i++) { cin >> v[i]; } cout << "Enter element that you want to search:" << endl; cin >> search; for(int i = 0; i < num; i++) { ...

Double Diamond Star Pattern in C :Star, Number, Alphabet & Binary Patterns with Output

Diamond Star Pattern in C

Diamond Star Pattern in C

This program prints a diamond shaped star pattern using nested loops and conditional statements in C.

๐Ÿ” C Program Code:

#include <stdio.h>

int main() {
    int num;
    printf("Enter the number:\n");
    scanf("%d", &num);

    // Upper part of diamond
    for(int i = 0; i < num; i++) {
        for(int j = 0; j < (2 * num); j++) {
            if(i + j <= num - 1) {
                printf("*");
            } else {
                printf(" ");
            }
            if(i + num <= j) {
                printf("*");
            } else {
                printf(" ");
            }
        }
        printf("\n");
    }

    // Lower part of diamond
    for(int i = 0; i < num; i++) {
        for(int j = 0; j < (2 * num); j++) {
            if(i >= j) {
                printf("*");
            } else {
                printf(" ");
            }
            if(i >= ((2 * num) - 1) - j) {
                printf("*");
            } else {
                printf(" ");
            }
        }
        printf("\n");
    }

    return 0;
}

๐Ÿ“Œ How It Works:

  • The program takes an integer input num which controls the size of the diamond.
  • The first pair of nested loops prints the upper half of the diamond:
    • Stars are printed on the left and right edges based on the conditions i + j <= num - 1 and i + num <= j.
    • Spaces fill the middle region, creating a hollow diamond shape.
  • The second pair of nested loops prints the lower half of the diamond:
    • Stars print based on conditions i >= j and i >= (2*num - 1) - j forming the symmetrical bottom.
  • Together, these loops form a complete diamond star pattern.

๐Ÿ’ป Sample Output for num=7:

* * * * * * * * * * * * * *
* * * * * * * * * * * *
* * * * * * * * * *
* * * * * * * *
* * * * * *
* * * *
* *
* *
* * * *
* * * * * *
* * * * * * * *
* * * * * * * * * *
* * * * * * * * * * * *
* * * * * * * * * * * * * *

Double Diamond Star Pattern in C

Double Diamond Star Pattern in C

This program prints a double diamond pattern of stars using nested loops in C.

๐Ÿ” C Program Code:

#include <stdio.h>

int main() {
    int n;
    printf("Enter the number:\n");
    scanf("%d", &n);

    // Upper part of pattern
    for (int i = 0; i < n; i++) {
        // Left stars
        for (int j = 0; j < n - i; j++) {
            printf("* ");
        }
        // Spaces in middle
        for (int j = 0; j < 2 * i; j++) {
            printf("  ");
        }
        // Right stars
        for (int j = 0; j < n - i; j++) {
            printf("* ");
        }
        printf("\n");
    }

    // Lower part of pattern
    for (int i = 0; i < n; i++) {
        // Left stars
        for (int j = 0; j <= i; j++) {
            printf("* ");
        }
        // Spaces in middle
        for (int j = 0; j < 2 * (n - i - 1); j++) {
            printf("  ");
        }
        // Right stars
        for (int j = 0; j <= i; j++) {
            printf("* ");
        }
        printf("\n");
    }

    return 0;
}

๐Ÿ“Œ How It Works:

  • The first for loop prints the upper half of the double diamond.
  • It prints decreasing stars on the sides and increasing spaces in the center.
  • The second for loop prints the lower half with increasing stars on the sides and decreasing spaces in the center.
  • This creates a symmetric double diamond star pattern.

๐Ÿ’ป Sample Output for n=7:

* * * * * * * * * * * * * *
* * * * * * * * * * * *
* * * * * * * * * *
* * * * * * * *
* * * * * *
* * * *
* *
* *
* * * *
* * * * * *
* * * * * * * *
* * * * * * * * * *
* * * * * * * * * * * *
* * * * * * * * * * * * * *

Comments

Popular Posts

๐ŸŒ™