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Add One to Number Represented by Array In C
➕ Add One to Number Represented by Array
#include <stdio.h>
int main()
{
int size;
// printf("Enter a array size: ");
scanf("%d", &size);
int a[size];
// printf("Enter a array elements: ");
for (int i = 0; i < size; i++)
{
scanf("%d", &a[i]);
}
int num = 0;
for (int i = 0; i < size; i++)
{
num = num * 10 + a[i];
}
num += 1;
printf("\nNumber after adding 1: %d\n", num);
int temp = num;
int result[10];
int index = 0;
while (temp > 0)
{
result[index++] = temp % 10;
temp /= 10;
}
printf("Result in array: ");
for (int i = index - 1; i >= 0; i--)
{
printf("%d ", result[i]);
}
printf("\n");
return 0;
}
๐ Explanation:
๐น This program reads digits of a number into an array.
๐น Combines those digits to form the actual number using positional multiplication.
๐น Adds 1 to the number.
๐น Breaks the result back into digits and stores them in another array.
๐น Finally, it prints the updated digits from the result array.
๐งช Sample Output:
Input:
5
1 2 3 4 5
Output:
Number after adding 1: 12346
Result in array: 1 2 3 4 6
๐ท️ Keywords:
add one to number in array, C program number to array, digit manipulation in C, array math in C, convert array to integer, beginner C array program
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