Check if a Number is Divisible by 2 and 3 in C

July 10, 2026

C++ Program to Perform Linear Search on a Vector

C++ Program to Perform Linear Search on a Vector Introduction In this C++ program, we will learn how to perform a Linear Search on a vector. The program first takes the size of the vector and its elements as input. Then it asks the user for the element to search. If the element is found, it displays the index where it is located. Otherwise, it displays a message indicating that the element is not found. C++ Program #include<bits/stdc++.h> using namespace std; int main() { int num, search, found = 0; cout << "Enter the size of the vector:" << endl; cin >> num; vector<int> v(num); cout << "Enter " << num << " elements in vector:" << endl; for(int i = 0; i < num; i++) { cin >> v[i]; } cout << "Enter element that you want to search:" << endl; cin >> search; for(int i = 0; i < num; i++) { ...

✅ CHECK IF A NUMBER IS DIVISIBLE BY 2 AND 3 IN C

#include <stdio.h>

int main() {
    int num;

    printf("Enter a number:\n");
    scanf("%d", &num);

    if (num % 2 == 0 && num % 3 == 0) {
        printf("%d is perfectly divisible by both 2 and 3.\n", num);
    } else {
        printf("%d is NOT divisible by both 2 and 3.\n", num);
    }

    return 0;
}

🧠 Explanation:

This program checks whether a given number is divisible by both 2 and 3.

It uses num % 2 == 0 to check divisibility by 2.
And num % 3 == 0 to check divisibility by 3.
If both are true, it prints that the number is divisible by both.

🖥️ Sample Output:

Enter a number:
12
12 is perfectly divisible by both 2 and 3.

🔑 Keywords:

C program to check divisibility, modulus operator, if condition, logical AND, basic C program.

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C++ Program to Perform Linear Search on a Vector