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C Program to Solve Two Sum Using Brute Force (With Algorithm & Output)

 Introduction The Two Sum problem is a popular coding interview question where we must find two indices of an array whose values add up to a given target. This program demonstrates a simple brute-force solution in C using nested loops and dynamic memory allocation. Problem Statement Given an integer array and a target value, return the indices of the two numbers such that they add up to the target. Each input has exactly one solution, and the same element cannot be used twice. The result should return the indices, not the values. If no solution exists, return NULL.  Algorithm / Logic Explanation Start the program. Traverse the array using a loop from index 0 to numsSize - 1 . Inside this loop, use another loop starting from i + 1 to numsSize - 1 . For every pair (i, j) , check if nums[i] + nums[j] == target . If condition becomes true: Allocate memory for 2 integers using malloc() . Store indices i and j . Set returnSize = 2 . Return the result poi...
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Print Even and Odd Numbers in a Range using C

Print Even and Odd Numbers in a Range using C

✅ Print Even and Odd Numbers Between Two Numbers in C

#include <stdio.h>

int main() {
    int start, end;

    // Input the range
    printf("Enter the starting number: ");
    scanf("%d", &start);
    printf("Enter the ending number: ");
    scanf("%d", &end);

    // Validate input
    if (start > end) {
        printf("Invalid input! Starting number must be less than or equal to ending number.\n");
        return 1;
    }

    // Print even numbers
    printf("\nEven numbers between %d and %d are:\n", start, end);
    for (int i = start; i <= end; i++) {
        if (i % 2 == 0) {
            printf("%d ", i);
        }
    }

    // Print odd numbers
    printf("\n\nOdd numbers between %d and %d are:\n", start, end);
    for (int i = start; i <= end; i++) {
        if (i % 2 != 0) {
            printf("%d ", i);
        }
    }

    printf("\n");
    return 0;
}

📘 Explanation:

✅ This program takes two integers from the user: starting and ending values.
✅ It uses two separate for loops to filter even and odd numbers:
➤ i % 2 == 0 condition is used to check even numbers.
➤ i % 2 != 0 condition is used for odd numbers.
✅ It handles invalid input if the start value is greater than the end value.

🧾 Sample Output:

Enter the starting number: 10
Enter the ending number: 20

Even numbers between 10 and 20 are:
10 12 14 16 18 20

Odd numbers between 10 and 20 are:
11 13 15 17 19

🔑 Keywords:

even odd numbers in C, print even odd in range, C programming loops, beginner C logic, number filtering, % modulus operator

📌 Hashtags:

#CProgramming #EvenOdd #LoopsInC #BeginnerPrograms #LogicalThinking #NumberRange #CodingBasics

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