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C Program to Find Remainder Without Using % Operator
✅ C Program to Find Remainder Without Using % Operator
#include <stdio.h>
int main() {
int a, b;
printf("Enter two numbers (a %% b): ");
scanf("%d %d", &a, &b);
int sign = 1;
if (a < 0) { a = -a; sign = -sign; } // handle negative dividend
if (b < 0) { b = -b; } // divisor just made positive
while (a >= b) {
a -= b; // keep subtracting divisor from dividend
}
printf("Remainder is: %d\n", sign * a);
return 0;
}
๐ Explanation:
This program calculates the remainder without using the modulus (%) operator. It repeatedly subtracts the divisor from the dividend until the remainder is smaller than the divisor.
- Handles negative dividends by tracking the sign.
a -= b;keeps subtracting divisor until remainder is less.- Final result is adjusted using
sign * a.
๐งพ Sample Output:
Enter two numbers (a % b): 17 5 Remainder is: 2 Enter two numbers (a % b): -17 5 Remainder is: -2
๐ Keywords:
C program remainder without %, modulus without operator, remainder using subtraction, arithmetic operators in C, tricky C programs
๐ Hashtags:
#CProgramming #Modulo #InterviewPrep #LearnC #BitwiseTricks
๐ Search Description:
Learn how to find remainder in C without using modulus (%) operator. Uses repeated subtraction and handles negative numbers. Includes explanation and sample output.
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