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Solve LeetCode 3 Longest Substring Without Repeating Characters in C++ using the sliding window

Longest Substring Without Repeating Characters in C++ LeetCode 3 · sliding window · last index array Table of Contents Problem Statement Approach Algorithm C++ Program Input Sample Output Output Explanation Dry Run Flow of Execution Time Complexity Space Complexity Applications Key Points Interview Questions Frequently Asked Questions Conclusion Problem Statement 3. Longest Substring Without Repeating Characters Given a string s , find the length of the longest substring that contains no repeating characters. A substring is a continuous part of the string, so "pwke" is a subsequence of "pwwkew" but not a substring. Approach We use a sliding window . The window is the part of the string between start and end , and we always keep it free of repeated characters. An array lastIndex of size 128 remembers the most recent position of every ASCII ...

C++ Program to Subtract Two Complex Numbers using Operator Overloading

C++ Program to Subtract Two Complex Numbers using Operator Overloading

✅ C++ Program to Subtract Two Complex Numbers using Operator Overloading

#include<iostream>
using namespace std;
class complex
{
    public:
    int real,imag;
    void input()
    {
        cout<<"Enter real part:\n";
        cin>>real;
        cout<<"Enter imag part:\n";
        cin>>imag;
    }
    complex()
    {
        real=0;
        imag=0;
    }
    complex(int r,int i )
    {
        real=r;
        imag=i;
    }
    
    complex operator-(complex&obj)
    {
        complex result;
        result.real=real-obj.real;
        result.imag=imag-obj.imag;
        return result;
    }
    void display()
    {
        cout<<real<<"-"<<imag<<"i"<<"\n";
    }
};
int main( )
{
    complex c1,c2,c3;
    cout<<"Enter first part:\n";
    c1.input();
    cout<<"Enter second part:\n";
    c2.input();
    cout<<"Result after subtraction:\n";
    c3=c1-c2;
    c3.display();
}
  

๐Ÿ“˜ Explanation:

This program demonstrates operator overloading in C++. The - operator is overloaded to subtract two complex numbers.

  • Constructors: Default and parameterized constructors are used.
  • operator-() subtracts the real and imaginary parts of two complex numbers.
  • display() prints the result in the standard complex number format.

๐Ÿงพ Sample Output:

Enter first part:
Enter real part:
5
Enter imag part:
3
Enter second part:
Enter real part:
2
Enter imag part:
1
Result after subtraction:
3-2i
  

๐Ÿ”‘ Keywords:

C++ program complex number subtraction, operator overloading in C++, OOP concepts in C++, C++ interview program, complex class in C++

๐Ÿ“Œ Hashtags:

#CPlusPlus #OperatorOverloading #ComplexNumbers #OOP #CodingInterview

๐Ÿ” Search Description:

C++ program to subtract two complex numbers using operator overloading. Demonstrates constructors, operator overloading, and object-oriented programming concepts.

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