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C Program to Check Prime Number Using Efficient Logic

  Introduction A prime number is a number that has exactly two distinct positive divisors: 1 and itself. In this program, we check whether a given number is prime or not using a simple and efficient logic. This type of program is commonly used in mathematics, competitive programming, and basic algorithm learning for beginners in C programming. Problem Statement The task is to write a C program that determines whether a given integer is a prime number or not. The program takes a single integer input from the user and analyzes its divisibility. If the number has no divisors other than 1 and itself, it should be identified as a prime number; otherwise, it is not prime. This problem is important in number theory and has practical relevance in areas such as cryptography, data validation, and algorithm design.  Algorithm / Logic Explanation To check whether a number is prime, we need to verify that it is not divisible by any number other than 1 and itself. The algorithm follows a si...

C++ Program for Complex Numbers Using Operator Overloading

C++ Program for Complex Numbers Using Operator Overloading

✅ C++ Program for Complex Number Operations Using Operator Overloading

#include <iostream>
#include <cmath>
using namespace std;

class complex
{
public:
    float real, image;

    complex()
    {
        real = 0;
        image = 0;
    }

    void input()
    {
        cout << "Enter real part: ";
        cin >> real;
        cout << "Enter imaginary part: ";
        cin >> image;
    }

    complex operator+(complex &obj)
    {
        complex temp;
        temp.real = real + obj.real;
        temp.image = image + obj.image;
        return temp;
    }

    complex operator-(complex &obj)
    {
        complex temp;
        temp.real = real - obj.real;
        temp.image = image - obj.image;
        return temp;
    }

    complex operator*(complex &obj)
    {
        complex temp;
        temp.real = (real * obj.real) - (image * obj.image);
        temp.image = (real * obj.image) + (image * obj.real);
        return temp;
    }

    complex operator/(complex &obj)
    {
        complex temp;
        float denom = (obj.real * obj.real) + (obj.image * obj.image);

        temp.real = (real * obj.real + image * obj.image) / denom;
        temp.image = (image * obj.real - real * obj.image) / denom;

        return temp;
    }

    complex conjugate()
    {
        complex temp;
        temp.real = real;
        temp.image = -image;
        return temp;
    }

    float modulus()
    {
        return sqrt((real * real) + (image * image));
    }

    void display()
    {
        cout << real << " + " << image << "i" << endl;
    }
};

int main()
{
    complex c1, c2, c3;

    cout << "Enter first complex number:\n";
    c1.input();

    cout << "\nEnter second complex number:\n";
    c2.input();

    c3 = c1 + c2;
    cout << "Addition:\n";
    c3.display();

    c3 = c1 - c2;
    cout << "Subtraction:\n";
    c3.display();

    c3 = c1 * c2;
    cout << "Multiplication:\n";
    c3.display();

    c3 = c1 / c2;
    cout << "Division:\n";
    c3.display();

    c3 = c1.conjugate();
    cout << "Conjugate:\n";
    c3.display();

    cout << "Modulus:\n";
    cout << c1.modulus() << endl;

    return 0;
}
  

๐Ÿ“˜ Explanation:

This program demonstrates operator overloading in C++ for performing arithmetic operations on complex numbers. Each operator is overloaded using mathematical formulas.

  • + → Adds two complex numbers
  • - → Subtracts two complex numbers
  • * → Multiplies two complex numbers
  • / → Divides two complex numbers
  • Conjugate → Changes sign of imaginary part
  • Modulus → Calculates magnitude

๐Ÿ“ Mathematical Formulas Used:

Let z₁ = a + bi
    z₂ = c + di

Addition       :(a+bi)+(c+di)=(a+c)+(b+d)i
Subtraction    :(a+bi)−(c+di)=(a−c)+(b−d)i
Multiplication : (a+bi)(c+di)=(ac−bd)+(ad+bc)i
Division       :a+bi/c+di=(ac+bd)+(bc-ad)i/c^2+d^2
Conjugate      : a − bi
Modulus        : √(a² + b²)
  

๐Ÿงพ Sample Output:

Enter real part: 4
Enter imaginary part: 5
Enter real part: 2
Enter imaginary part: 3

Addition:
6 + 8i
Subtraction:
2 + 2i
Multiplication:
-7 + 22i
Division:
1.77 + -0.15i
Conjugate:
4 + -5i
Modulus:
6.40
  

๐Ÿ”‘ Keywords:

C++ complex number program, operator overloading, complex arithmetic, C++ OOP example, complex class in C++

๐Ÿ“Œ Hashtags:

#CPlusPlus #OperatorOverloading #ComplexNumbers #OOP #CPPBasics #Programming #1printf

๐Ÿ” Search Description:

Learn how to perform complex number operations in C++ using operator overloading. Includes formulas, explanation, sample output, and dark-themed code.

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