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C++ Program Using Inline Function to Check Even or Odd
C++ Program Using Inline Function to Check Even or Odd
#include <iostream>
using namespace std;
inline int even(int num)
{
return (num % 2 == 0);
}
int main()
{
int n;
cout << "Enter the number: ";
cin >> n;
if(even(n))
cout << n << " is an Even number" << endl;
else
cout << n << " is an Odd number" << endl;
return 0;
}
๐ Explanation:
This program demonstrates the use of an inline function in C++ to determine whether a given number is even or odd.
The inline function even() checks if the number is divisible by 2.
If the condition is true, the function returns 1 (true), otherwise it returns 0 (false).
Inline functions are commonly used for small and frequently called functions because they reduce function call overhead and improve performance.
๐งพ Sample Output:
Enter the number: 8 8 is an Even number
๐ Keywords:
C++ inline function, even odd program in C++, inline even function, C++ number programs, C++ basics
๐ Search Description:
Learn how to check whether a number is even or odd in C++ using an inline function. This simple program includes explanation, syntax, and sample output.
๐ Hashtags:
#CPlusPlus #InlineFunction #EvenOdd #CPPBasics #Programming #1printf
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