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C++ Program to Perform Linear Search on a Vector

  C++ Program to Perform Linear Search on a Vector Introduction In this C++ program, we will learn how to perform a Linear Search on a vector. The program first takes the size of the vector and its elements as input. Then it asks the user for the element to search. If the element is found, it displays the index where it is located. Otherwise, it displays a message indicating that the element is not found. C++ Program #include<bits/stdc++.h> using namespace std; int main() { int num, search, found = 0; cout << "Enter the size of the vector:" << endl; cin >> num; vector<int> v(num); cout << "Enter " << num << " elements in vector:" << endl; for(int i = 0; i < num; i++) { cin >> v[i]; } cout << "Enter element that you want to search:" << endl; cin >> search; for(int i = 0; i < num; i++) { ...

Sort Items Based on Risk Severity (0, 1, 2) in C

Sort Items Based on Risk Severity (0, 1, 2)

✅ Sort Items Based on Risk Severity

Airport security officials have confiscated several item of the passengers at the security check point. All the items have been dumped into a huge box (array). Each item possesses a certain amount of risk[0,1,2]. Here, the risk severity of the items represent an array[] of N number of integer values. The task here is to sort the items based on their levels of risk in the array. The risk values range from 0 to 2.

Example :

Input :

7  -> Value of N

[1,0,2,0,1,0,2]-> Element of arr[0] to arr[N-1], while input each element is separated by new line.

Output :

0 0 0 1 1 2 2  -> Element after sorting based on risk severity
  

Example 2:

input : 10  -> Value of N 

[2,1,0,2,1,0,0,1,2,0] -> Element of arr[0] to arr[N-1], while input each element is separated by a new line.

Output : 

0 0 0 0 1 1 1 2 2 2  ->Elements after sorting based on risk severity.
  

Explanation:

In the above example, the input is an array of size N consisting of only 0’s, 1’s and 2s. The output is a sorted array from 0 to 2 based on risk severity.


#include <stdio.h>

/* Function to sort colors (0, 1, 2) */
void sortColors(int* nums, int numsSize)
{
    int low = 0, mid = 0, high = numsSize - 1;

    while (mid <= high)
    {
        if (nums[mid] == 0)
        {
            int temp = nums[low];
            nums[low] = nums[mid];
            nums[mid] = temp;

            low++;
            mid++;
        }
        else if (nums[mid] == 1)
        {
            mid++;
        }
        else   // nums[mid] == 2
        {
            int temp = nums[mid];
            nums[mid] = nums[high];
            nums[high] = temp;

            high--;
        }
    }
}

int main()
{
    int n;

    printf("Enter the number of elements: ");
    scanf("%d", &n);

    if (n <= 0)
    {
        printf("Invalid input\n");
        return 0;
    }

    int nums[n];

    printf("Enter elements (0, 1, 2 only):\n");
    for (int i = 0; i < n; i++)
    {
        scanf("%d", &nums[i]);
    }

    /* Call sorting function */
    sortColors(nums, n);

    printf("Sorted array:\n");
    for (int i = 0; i < n; i++)
    {
        printf("%d ", nums[i]);
    }

    return 0;
}
  

๐Ÿ“Œ Hashtags:

#CProgramming #ArraySorting #BitManipulation #Programming #1printf

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